14x^2+15x-35=0

Solution for 14x^2+15x-35=0 equation:

14x^2+15x-35=0

a = 14; b = 15; c = -35;
Δ = b2-4ac
Δ = 152-4·14·(-35)
Δ = 2185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{2185}}{2*14}=\frac{-15-\sqrt{2185}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{2185}}{2*14}=\frac{-15+\sqrt{2185}}{28}
$